Showing posts with label Practical. Show all posts
Showing posts with label Practical. Show all posts

Monday, December 7, 2020

To determine the Energy Band Gap of a Semiconductor by using PN Junction Diode.

Aim: To determine the Energy Band Gap of a Semiconductor by using PN Junction Diode. Apparatus: Energy band gap kit containing a PN junction diode placed inside the temperature controlled electric oven, microammeter, voltmeter and connections brought out at the socket, a mercury thermometer to mount on the front panel to measure the temperature of oven. Formula Used: The reverse saturation current, Is is the function of temperature (T) of the junction diode. For a small range of temperatures, the relation is expressed as, 
Where, T is temperature in Kelvin (K) and Eg is the band gap in electron volts (eV). Graph between 103/T as abscissa and log10 Is as ordinate will be a straight line having slope = 5.036 Eg Hence band gap, 
Theory: A semi-conductor (either doped or intrinsic) always possesses an energy gap between its valence and conduction bands (fig.1). For the conduction of electricity, a certain amount of energy is to be given to the electron so that it can jump from the valence band to the conduction band. The energy so needed is the measure of the energy gap (Eg) between the top and bottom of valence and conduction bands respectively. In case of insulators, the value of Eg varies from 3 to 7 eV. However, for semiconductors, it is quite small. For example, in case of germanium, Eg = 0.72 eV and in case of silicon, Eg = 1.1 eV.  
In semi-conductors at low temperatures, there are few charge carriers to move, so conductivity is quite low. However, with increase in temperature, more number of charge carriers get sufficient energy to be excited to the conduction band. This lead to increase in the number of free charge carriers and hence increase in conductivity. In addition to the dependence of the electrical conductivity on the number of free charges, it also depends on their mobility. The mobility of the charge carriers, however decreases with increasing temperature. But on the average, the conductivity of the semiconductors rises with rise in temperature. To determine the energy band gap of a semi-conducting material, we study the variation of its conductance with temperature. In reverse bias, the current flowing through the PN junction is quite small and internal heating of the junction does not take place. When PN junction is placed in reverse bias as shown in fig.2(a), the current flows through the junction due to minority charge carriers only. The concentration of these charge carriers depend on band gap Eg. The saturation value, Is of reverse current depends on the temperature of junction diode and it is given by the following equation,

Precautions: The following precautions should be taken while performing the experiment: 1. The diode must be reverse biased. 2. Do not exceed the temperature of the oven above 100℃ to avoid over heating of the diode. 3. The voltmeter and ammeter reading should initially be at zero mark. 4. Bulb of the thermometer should be inserted well in the oven. 5. Readings of microammeter should be taken when the temperature is decreasing. 6. Readings of current and temperature must be taken simultaneously. Sample viva voce questions: 1. What is PN junction diode? 2. What do you understand by band gap of a semi-conductor? 3. What do you mean by valence band, conduction band and forbidden band? 4. How many types of semi-conductors are there? 5. What are P-type and N-type semi-conductors? 6. Define doping and dopant. 7. Why P-type (N-type) semi-conductor is called Acceptor (Donor)? 8. What do you mean by Fermi energy level? 9. What is the position of Fermi level in an intrinsic semi-conductor and in a p-type or n-type semi-conductor with respect to the positions of valence and conduction bands? 10. What do you mean by forward biasing and reverse biasing? 11. Why diode is reverse biased in determining the band gap of semi-conductor? 12. What is the shape of graph between log10 Is and 103/ T? How do you find band gap energy from this graph? 13. Why conductivity of metals decreases with increase in temperature? 14. Why conductivity of a semi-conductor increases with increase in temperature? References:  Solid State Electronic Devices by Streetman and Banerjee  B.sc Practical Physics by Geeta Sanon 

 

Friday, September 25, 2020

To determine the refractive index of the material of a given prism using a spectrometer.

 REFRACTIVE INDEX OF PRISM USING A SPECTROMETER

AIM:- To determine the refractive index of the material of a given prism using a spectrometer.


APPARATUS:- A spectrometer, a spirit level, a source of monochromatic light (sodium vapour lamp), a glass prism, a magnifying lens and a reading lamp.


Theory:- When a beam of light strikes on the surface of transparent material (glass, water, quartz crystal, etc.), the portion of the light is transmitted and and other portion is reflected. The transmitted light ray has small deviation of the path from the incident angle. This is called refraction. Refraction is due to the change in speed of light while passing through the medium. It is given by snell’s law 

where i is the angle of incident, r is the angle of refraction, n1 is the refractive index of the first medium and n2 is the refractive index of the second medium.

To determine the angle of the Prism:
Make coincide the slit with the cross wire using fine angle adjusting slider. Then note the reading in the tabular coloumn. Move the telescope in the opposite direction and do the same. Find the difference between two angle ie 2θ.

OBSERVATION:- Write down the actual readings taken upon the apparatus.Take at least three readings of each observation and record them in tabular form as far as possible. Avoid overwriting. This part of the record of the experiment is very important and hence should be written clearly and carefully.

CALCULATION:- Write down the formula to be used and substitute the values obtained to calculate the result. Simplification should be done on the left page. Do logarithmic calculation.

RESULTS:- Write clearly the actual result obtained from your observations. 
PRECAUTIONS AND SOURCES OF ERRORS:- Give the precautions taken when conducting the experiment. Discuss the reasons for not getting standard results.

EXPERIMENTAL RESULTS(Approx):- 
(1)  Angle of Prism = 60°
(2) Angle of Minimum Deviation = 37.2° (degrees).
(3) Refractive Index Of Prism = 1.5